几道数学题,明天就要
1、(x+y)^2 -4(x+y-1) (因式分解)
2、(x+y)^(m+1)-(x+y)^(m-1) (因式分解)(m为大于1的整数
3、 3x^2 -6x+1 (配方法解因式)
4、x^(n+1)—8x^n +16x^(n—1) (因式分解)
5、已知1/a — 1/b=1/(a+b) ,求(b^2)/(a^2)+(a^2)/(b^2)
6、已知x+y=—4,xy=3 ,求(x+2)/(y+2)+(y+2)/(x+2)的值
7、已知分式(ax+7)/(bx+11)对一切有意义的x的值都有相同的值,求a、b应满足的条件.
人气:464 ℃ 时间:2020-03-24 10:20:46
解答
1.原式=(x+y)^2-4(x+y)+4=(x+y-2)^22.原式=(x+y)(x-y)(m-1)3.原式=3x^2-6x+3-2=3(x-1)^2-24.原式=(x-4)^(n-1)5.因为:1/a-1/b=(b-a)/ab,所以得出:(b-a)/ab=1/(a+b),十字相乘得:b^2-a^2=ab即:b^2=ab+a^2,(b^2)/(a^...
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