求定积分 ∫(上1下0)1/(x^2-2x-3)dx_数学解答

求定积分 ∫(上1下0)1/(x^2-2x-3)dx

人气：211 ℃　时间：2020-04-03 02:02:42

解答

∫[0,1] 1/(x^2-2x-3)dx
=1/5∫[0,1] [1/(x-3)-1/(x+2)]dx
=1/5[ln|x-3|-ln|x+2|] [0,1]
=1/5(ln2-ln3-ln2+ln2)
=0