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数学
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还有已知项数为2n+1等差数列,S奇-S偶=?S奇/S偶=?
人气:376 ℃ 时间:2019-08-21 18:43:00
解答
奇数项有n+1项,偶数项有n项
奇数项、偶数项分别成等差数列
S奇=(A1+A(2n+1))×(n+1)/2
=(A1+A1+2nd)×(n+1)/2
=(A1+nd)×(n+1)
=(n+1)A(n+1)
S偶=(A2+A(2n))×n/2
=(A1+d+A1+(2n-1)d)×n/2
=(A1+nd)×n
=nA(n+1)
S奇-S偶=(n+1)A(n+1)-nA(n+1)=A(n+1)
S奇/S偶=(n+1)A(n+1)/nA(n+1)=(n+1)/n
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