所以f(x)在π/6+kπ
2、x属于[-5π/12,π/3]
2x+π/6属于[-2π/3,5π/6]
sin(2x+π/6)属于[-√3/2,1]
f(x)属于[-√3-1,1]
希望对你有帮助~那单调递增区间怎么算？-π/2+2kπ<2x+π/6<π/2+2kπ，k属于Z 2π/3+kπ
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