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计算题:(a^3·b^m)3·b^2 (2)2^4+4^5×(-0.125)^4
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人气:483 ℃ 时间:2020-05-22 07:14:50
解答
(a^3·b^m)^3·b^2
=a^9*b^(3m)*b^2
=a^9*b^(3m+2)
2^4+4^5×(-0.125)^4
=2^4+4^5×(1/8)^4
=2^4+2^10/2^12
=16+1/4
=16又1/4
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