因为|x-1|=2所以x-1=±2解得：x=3或x=-1当x=3时√x²-8x+16－√4x²-4x+1=√(x-4)²－√(2x-1)²=|x-4|-|2x-1|=1-5=-4当x=-1时√x²-8x+16－√4x²-4x+1=√(x-4)²－√(2x-1)²=|x-...