已知实数x、y满足
,若不等式a(x
2+y
2)≥(x+y)
2恒成立,则实数a的最小值是______.
人气:138 ℃ 时间:2019-12-01 13:39:21
解答
实数x、y满足2x−y≤0x+y−5≥0y−4≤0的可行域是一个三角形,三角形的三个顶点分别为(1,4),(2,4),(53,103)与原点连线的斜率分别为4,2,∴yx∈[2,4]a(x2+y2)≥(x+y)2等价于a≥1+2yx+xy∵yx∈[2,4]∴...
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