(2x+y)(2x-y)+(x+y)^2-2(2x^2-xy)
=4x²-y²+x²+2xy+y²-4x²+2xy
=x²+2xy+2xy
=x²+4xy
=x(x+4y)
如果是化简,请给出x,y的值,请点击我回答下方的【追问】没有值(2x+y)(2x-y)+(x+y)^2-2(2x^2-xy) =4x²-y²+x²+2xy+y²-4x²+2xy =x²+2xy+2xy =x²+4xy =x(x+4y)=x^2+4xy