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求极限lim(1/x2-1/(xtanx)) x→0
人气:478 ℃ 时间:2020-01-09 05:03:02
解答
lim (1/x^2 - 1/xtanx)
= lim(xtanx - x^2)/(x^3 * tanx) 约去一个tanx
= lim (tanx - x)/x^3 上下都求导数(罗必达法则)
= lim (secx * secx -1)/3x^2
= lim (tanx * tanx)/3x^2
= 1/3
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