,[x^2-4]/[x^2+x+1]的平方/[x^3-2x^2]/[x^3+x^2+x]的平方*[x/x+2]^3
=[(x+2)(x-2)/(x^2+x+1)^2]*[x^2(x^2+x+1)^2/x^2(x-2)】*x^3/(x+2)^3
=x^3/(x+2)^2
=(-2/3)^3/(-2/3+2)^2
=-1/6