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[9^(4n+2)-9^(4n+1)]/81^(2n-1)
这道题怎么做
人气:168 ℃ 时间:2020-06-07 00:01:02
解答
[9^(4n+2)-9^(4n+1)]/81^(2n-1)
=[9*9^(4n+1)-9^(4n+1)]/9^(4n-2)
=[8*9^(4n+1)]/9^(4n-2)
=[8*9^(+1)]/9^(-2)
=8*9^3
=5832
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