若f(x)=(m-1)x的平方+2mx+3为偶函数,则f(x)在区间(-3,-1)上是单调的什么函数
人气:338 ℃ 时间:2019-08-17 17:04:34
解答
因为函数是偶函数所以f(x)=f(-x)
f(x)=(m-1)x^2+2mx+3
f(-x)=(m-1)x^2-2mx+3
x∈(-∞,-∞),则有mx=0
所以m=0
所以f(x)=-x^2+3
所以(-3,-1)是增函数
推荐
- 若函数f(x)=(m-1)x2+mx+3 (x∈R)是偶函数,则f(x)的单调减区间是_.
- 已知函数f(x)=(M-1)x平方|2mx+3为偶函数,则f(x)在区间(-5,-2)上是?
- 函数f(x)=(m-1)x^2+2mx+3为偶函数,则f(x)在区间(-5,-3)上____.
- f(x)=(m-1)x^2+2mx+3是偶函数,则函数f(x)的单调递增区间是?
- 设函数f(x)=(m-1)x平方+2mx+3是偶函数,则它在
- Learn to be independent When I was a child,I promised to try to remember as much as I could about my childhood.Because f
- 甲,乙两堆煤的重量比是4比5从甲堆中运出260吨到乙堆,现在比是3比5求乙煤
- 悲伤感受得到情感的优美的句子!或者,直接性的表达作者情感的语句!悲喜交加
猜你喜欢