x^2+y^2+2x+10=6y
x^2+y^2+2x+10-6y=0
(x+1)^2+(y-3)^2=0
且(x+1)^2≥0,(y-3)^2≥0
所以(x+1)^2＝0,(y-3)^2＝0
x=-1 y=3
所以y^x
=3^(-1)
=1/3