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1-sqr(x)/[1+sqr(x)]+sqr(x)+2求最值,
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人气:431 ℃ 时间:2020-04-15 15:41:04
解答
{1-sqr(x)/[1+sqr(x)]}之中1不在分母之中
1-sqr(x)/[1+sqr(x)]+sqr(x)+2
=1/[sqr(x)+1]+sqr(x)+1+1 (大于等于3)
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