已知cos(θ+π/6)=5/13,θ∈(0,π/2),求cosθ
人气:234 ℃ 时间:2020-06-28 10:01:39
解答
cos(θ+π/6)=5/13 θ∈(0,π/2),
sin(θ+π/6)=12/13
cosθ
=cos(θ+π/6-π/6)
=cos(θ+π/6)cos(π/6)+sin(θ+π/6)sin(π/6)
=5/13*√3/2+12/13x1/2
=(5√3+12)/26
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