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求y=1/[log2(x2-4x+3)]的定义域
人气:246 ℃ 时间:2020-09-07 21:22:35
解答
y=1/[log2(x2-4x+3)]的定义域 log2(x2-4x+3)≠0 and x2-4x+3>0x2-4x+3≠1 x2-4x+3>0x2-4x+2≠0 x2-4x+3>0x≠2+√2 and x≠ 2-√2 and( x3)定义域为(-∞,2-√2)∪(2-√2,1)∪(3,2+√2)∪ (2+√2,+ ∞)...
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