1,
Vy=gt=10*0.4=4m/s
tan53=Vy/Vo
8/6=4/Vo
Vo=3m/s
V合=5m/s
2,
X=Vo*t
=3*0.4
=1.2m
h=gt^2
=10*0.16/2
=0.9m
D=1.5m (落地点到抛出点的直线距离=1.5m）h=gt^2=10*0.16/2=0.9m ？？？不是0.8？Vo=3m/sV合=5m/s不太懂 麻烦解释下Vy=4m/s（竖直速度）Vo=3m/s(水平速度）勾股弦V=5m/s哦那h=gt^2=10*0.16/2=0.9m ？？？这个呢呵呵，完全一样：勾股弦3:4:5不是吧 10*0.16 是1.6 /2 是0.8吧那h=gt^2=10*0.16/2=5*0.16=0.8m我错了D=√(0.8^2+1.2^2)=√2.08m