lim【x→0】cosx/ln(1+x²)
=lim【x→0】(x²/2)/x²
=1/2

答案：1/2分子是cosx不是1-cosxsorry∵lim【x→0】ln(1+x²)=0 lim【x→0】cosx=1lim【x→0】ln(1+x²)/cosx=0所以lim【x→0】cosx/ln(1+x²)=∞