(x+1)/(x+2)-1/(x+7)=(x+2)/(x+3)-1/(x+6)方程两边同时乘以(x+2)(x+7)(x+3)(x+6)得：(x+1)(x+7)(x+3)(x+6)-(x+2)(x+3)(x+6)=(x+2)(x+6)(x+2)(x+7)-(x+2)(x+7)(x+3)整理得：(x+2)(x+3)-(x+6)(x+7)=0即：x^2+5x+6-(x^2...简便点说行不~~~~~O(∩_∩)O~~~~~~挑重点~~~啊？？？这个是 过程啊·····就是方程两边同时乘以最简公分母然后去括号 移项 合并同类项系数化1求解