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数学
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若sina+cosa=-√2,则tana+cota等于多少?
尽快、
人气:186 ℃ 时间:2020-01-29 22:16:33
解答
sina+cosa=-√2
两边平方
sin²a+cos²a+2sinacosa=2
1+2sinacosa=2
sinacosa=1/2
tana+cota
=sina/cosa+cosa/sina
=(sin²a+cos²a)/sinacosa
=1/sinacosa
=2
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