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∫(x+inx)/x^3dx在(1,e)上的定积分.
人气:235 ℃ 时间:2020-06-02 00:50:25
解答
∫(1,e)(x+inx)/x^3dx
=(-1/x)|(1,e)-∫(1,e)(lnx)d(1/2x^2)
=1+1/e+[-lnx/2x^2-1/4x^2]|(1,e)
=1+1/e+[-1/2e^2-1/4e^2]+1/4
=5/4+1/e-3/(4e^2)
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