> 数学 >
在三角形ABC中,D为AC上一点且AD等于BD等于BC,则角ABD等于多少
人气:343 ℃ 时间:2020-01-09 05:36:58
解答
设∠ABD = X .(按题中的条件无法确定∠ABD,还要加个条件:AB=AC)
已知,AD = BD = BC ,可得:∠BAD = ∠ABD = X ;
已知,AB = AC ,BD = BC ,可得:∠ABC = ∠BCD = ∠BDC = ∠BAD+∠ABD = 2X ;
因为,∠BAD+∠ABC+∠BCD = 5X = 180° ,
所以,X = 36° ,即有:∠ABD = 36° .
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版