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f(x)=(1+1/tanx)sin(x)^2
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人气:103 ℃ 时间:2020-06-11 15:01:56
解答
f(x)=(1+1/tanx)sin(x)^2
=sin(x)^2+sin(x)^2/tanx
=sin(x)^2+sin(x)cos(x)
=(1-cos(2x))/2+sin(2x)/2
=(sin(2x)-cos(2x))/2+1/2
=√2sin(2x-45°)/2+1/2
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