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1/(2/3)/(3/4)/(4/5)./(2008分之2009) /是除号
1/(2/3)/(3/4)/(4/5)........../(2009分之2008) 打错
人气:396 ℃ 时间:2019-10-08 12:30:28
解答
1/(2/3)/(3/4)/(4/5)./(2009分之2008)
=1/[(2/3)*(3/4)*(4/5)*...*(2008/2009)]
=1/(2/3*3/4*4/5*...*2008/2009)
=1/(2/2009)
=1*2009/2
=2009/2
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