y=ax^5+bx^3+cx-2,当x=-2时,y=6时;求当x=2时,y的值
人气:165 ℃ 时间:2020-09-20 16:34:51
解答
y=ax^5+bx^3+cx-2,
当x=-2时,y=6时;
y=a2^5+b2^3+2c-2=6
a2^5+b2^3+2c=8
求当x=2时
y=ax^5+bx^3+cx-2
=-a2^5-b2^3-2c-2
=-(a2^5+b2^3+2c)-2
=-8-2
=-10
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