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已知cosα-sinα=3√5/5,17π/12<α<7π/4,求sin2α和tan(π/4+α)
人气:437 ℃ 时间:2020-04-12 10:37:48
解答
cosα-sinα=3√5/5 平方得
1-sin2a=9/5
sin2a=-4/5 17π/12<α<7π/4
cos2a=-3/5
tan(π/4+α)
=(1+tana)/(1-tana)
=(sina+cosa)/(cosa-sina)
=(sina+cosa)^2/(cos^2a-sin^2a)
=(1+sin2a)/cos2a
=(1/5)/(-3/5)
=-1/3
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