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cos1°+cos2°+cos3°+.+cos360°
人气:109 ℃ 时间:2020-04-07 08:51:06
解答
cos1°+cos2°+cos3°+.+cos360°
=(cos1+cos181)+(cos2+cos182)+...+(cos180+cos360)
=(cos1-cos1)+(cos2-cos2)+...+(cos180-cos180)
=0
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