求过两圆c1:x^2 y^2-4x+2y=0和c2:x^2+y^2-2y-4=0的交点
且圆心在直线l:2x+4y-1=0上的元的方程
人气:189 ℃ 时间:2019-12-09 12:09:32
解答
在两圆交点的圆系方程为:x²+ y²-4x+2y+λ(x²+y²-2y-4)=0(不包括c2,且λ≠-1)即(1+λ)x²+(1+λ)y²-4x+2(1-λ)y-4λ=0圆心C:(2/(1+λ),(λ-1)/(1+λ))因C在l上故4/(1+λ)+4(λ-1)/(...
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