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(x+y)平方+2(x+1)+2y-1 因式分解
RT
人气:397 ℃ 时间:2020-03-23 14:23:29
解答
(x+y)²+2(x+1)+2y-1
=(x+y)²+2x+2+2y-1
=(x+y)²+2x+2y+1
=(x+y)²+2(x+y)+1
=(x+y+1)²
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