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分离常数法求值域的问题
1.f(x)=-2x+3/(x+1)
2.f(x)=4x+2/(3x+1) x∈[-2,-1/3)∪(-1/3,3)
人气:121 ℃ 时间:2020-04-18 20:02:50
解答
1.f(x)=-2x+3/(x+1)=[-2(x+1)+5]/(x+1)=-2+5/(x+1)f(x)≠-22.f(x)=4x+2/(3x+1) =[4/3(3x+1)+2/3]/(3x+1) =4/3+2/3/(3x+1)f(x)≠4/3 x∈[-2,-1/3)∪(-1/3,3)f(x)∈[ 4/3+2/3/(3(...
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