依照题意,(x^3-3x^2+mx+n)÷(x^2-2x+1)=g(x)……(x+2)
则x^3-3x^2+(m-1)x+(n-2)=(x^2-2x+1)·g(x)
拆项因式分
x^3-3x^2+(m-1)x+(n-2)=(x^2-2x+1)·x-[x^2-(m-2)x+(2-n)]
若要整除,则x^2-(m-2)x+(2-n)=x^2-2x+1
∴m-2=2、2-n=1
m=4、n=1