>
数学
>
求函数y=cosx+cos(x-
π
3
)(x∈R)的最大值和最小值.
人气:493 ℃ 时间:2019-08-18 12:39:53
解答
∵y=cosx+cos(x-
π
3
)
=cosx+cosxcos
π
3
+sinxsin
π
3
=
3
2
cosx+
3
2
sinx
=
3
(cos
π
6
cosx+sin
π
6
sinx)
=
3
cos(x-
π
6
),
∵-1≤cos(x-
π
6
)≤1,
∴y
max
=
3
,y
min
=-
3
.
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