设函数f(x)=lnx-ax 求函数的极值点
人气：191 ℃ 时间：2019-09-16 21:10:33
解答
f'(x)=1/x-a=0 得x=1/a 又因为f''(x)=-1/x²0；当x>1/a时,f(x)
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