若tan(2x-y)=3tan(x-2y)=3,则tan(x+y)=
人气:178 ℃ 时间:2020-05-26 12:01:04
解答
tan(x+y)=tan[(2x-y)+(x-2y)]=[tan(2x-y)+tan(x-2y)]/[1-tan(x-2y)*tan(2x-y)]
=(3+1)/(1-3*1)=-2
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