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1+n-m/m+2n÷m²-n²/m²+4mn+4n²=
人气:240 ℃ 时间:2020-03-21 13:41:35
解答
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1 +(n-m)/(m+2n) ÷ (m²-n²) / (m²+4mn+4n²)
= 1 + (n-m)/(m+2n) × (m+2n)² / [(m+n)(m-n)]
= 1 - (m+2n)/(m+n)
= [ (m+n)-(m+2n)] / (m+n)
= - n/(m+n)
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