a=2/1-(-1)^ma要意义则1-(-1)^m不等于0则m不等于偶数所以a=2/(1-(-1))=1a,b互为相反数a+b=0b=-a=-1b,c互为倒数bc=1c=1/b=-1ab+b^m-(b-c)^2009=1*(-1)+(-1)^m-(-1-(-1))^2009由于m不等于偶数所以（-1）^m=-1ab+b^m-(b...