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证明tan^θ-sin^2θ=tan^2θsin^2θ
证明(1)tan^θ-sin^2θ=tan^2θsin^2θ
(2)sin^4x+cos^4x=1-2sin^2cos^2x
(31-tan^2x/1+tan^2x=cos^2x-sin^2x
人气:244 ℃ 时间:2020-02-04 13:21:16
解答
(1)tan^2θ-sin^2θ=sin^2θ/cos^2θ-sin^2θ=(sin^2θ-sin^2cos^2θ)/cos^2θ=sin^2θ(1-cos^2θ)/cos^2θ=sin^4θ/cos^2θ=(sin^2θ/cos^2θ)sin^2θ=tan^2θsin^2θ(2)sin^4x+cos^4x=(sin^2x+cos^2x)^2-2sin^...
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