利用等式：
n(n+1) = (1/3)[(n+2)(n+1)(n) - (n+1)(n)(n-1)]
1×2＋2×3＋3×4＋……＋48×49＋49×50
=(1/3)[(3×2×1 - 0) + (4×3×2 - 3×2×1) + ...+ (51×50×49 - 50×49×48)]
=(1/3)(51×50×49)（上步中前后抵消）
=41650