行列式a b c 1 b c a 1 c a b 1|a b c 1||b c a 1||c a b 1||(b+c)/c (a+_数学解答

行列式a b c 1 b c a 1 c a b 1
|a b c 1|
|b c a 1|
|c a b 1|
|(b+c)/c (a+c)/2 (b+a)/2 1|

人气：478 ℃　时间：2020-04-16 21:31:30

解答

r4-(1/2)r2-(1/2)r3
a b c 1
b c a 1
c a b 1
0 0 0 0
= 0.