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若函数在y=2xˆ2+4x处的导数是8,求x○的值.,
人气:140 ℃ 时间:2020-02-02 13:44:20
解答
x₀ = 1
y = 2x² + 4x
y' = 4x + 4
y'|(x₀) = 8 => 4x₀ + 4 = 8 => x₀ = 1
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