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已知a=(2sinx,根号3sinx),b=(cosx,2sinx),c=(2cosx,sinx)(1)求a乘b和|b-c|
人气:294 ℃ 时间:2019-08-18 21:39:27
解答
a*b=2sinxcosx+(2根号3 )sin^x
=sin2x+根号3-(根号3)cos2x
=2sin(2x-π/3)+根号3
(|b-c|)^=b^+c^+2bc
=cos^x+4sin^x+4cos^x+sin^x+4cos^x+4sin^x
=9cos^x+9sin^x
=(9根号2)sin(x+π/4)
∴|b-c|=根号[(9根号2)sin(x+π/4)]
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