∵cos(π/6-a)=√3/3 ∴sin(π/6-a)=±√6/3, cos(5π/6+a)=cos[π-(π/6-a)]=-cos(π/6-a)=-√3/3 ∴sin(a-π/6)=-sin(π/6-a)=±√6/3 ∴原式=-√3/3-(±√6/3)=-√3/3-2/3