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已知3sina=-cosa,求值 (1)sina-3cosa/sina+3cosa (2)1+sinacosa
人气:179 ℃ 时间:2020-03-26 12:33:51
解答
3sina=-cosasina/cosa=-1/3∴tana=-1/3 (1)sina-3cosa/sina+3cosa =(tana-3)/(tana+3)=(-1/3-3)/(-1/3+3)=-5/4 (2)1+sinacosa=(sin²a+cos²a+sinacosa)/(sin²a+cos²a)=(tan²a+1+tana)/(...
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