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计算:sin(-1200°)·cos1230°+cos(-1020°)sin(-1050°)+tan1305°
人气:168 ℃ 时间:2020-06-19 19:05:27
解答
sin(-1200+360*4)*cos(1230-360*3)+cos(-1020+3*360)*-sin(-1050+360*3)+tan(1305-180*7)=sin(240)*cos(150)+cos(60)*sin(30)+tan(45)=[-sin(60)]*[-cos(30)]+cos(60)*sin(30)+tan(45)=-((根号)3)/2*-((根号)3)/2+1/...
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