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求值:sin(-1200°)•cos1290°+cos(-1020°)•sin(-1050°)+tan945°=______.
人气:460 ℃ 时间:2020-06-20 09:53:08
解答
sin(-1200°)•cos1290°+cos(-1020°)•sin(-1050°)+tan945°
=-sin120°cos210°+cos60°sin30°+tan225°
=
3
4
+
1
4
+1=2.
故答案为:2
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