两球的表面积之差为48π,它们的大圆周长之和为12π,两球半径之差为
人气:461 ℃ 时间:2019-10-11 20:52:20
解答
s1-s2=4*pi*(r1^2- r2^2)=48pi;
2*pi*(r1+r2)=12*pi;
化为方程形式:
x^2-一y^2=12;
x+y=6;
x=4;y=2;
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