v末= v初+at
v末 = 16 m/s
v初 = 10 m/s
a = 0.2 m^2/s
可得,t = （v末-v初）÷a=（ 16-10）÷ 0.2= 30 s
则坡路长度为 s = （v初+v末）*t / 2 = 390 m