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help me:分解因式:x-y-xx+2xy-yy+2=0
人气:416 ℃ 时间:2020-06-20 13:09:40
解答
x-y-x^2+2*x*y-y^2+2
=-(x+1-y)*(x-2-y)
=0
x-y+1=0
x-y-2=0
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