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数学
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(x+1)^2-4分之x-1,2-4x+2x^2分之1-x通分
人气:358 ℃ 时间:2020-03-22 01:27:02
解答
(x-1)/[(x+1)^2-4]
=(x+1)/(x+1+2)(x+1-2)
=(x+1)/(x+3)(x-1)
=2(x+1)/2(x+3)(x-1)
(1-x)/(2-4x+2x^2)
=-(x-1)/2(x-1)^2
=-1/2(x-1)
=-(x+3)/2(x+3)(x-1)
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