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通分(x+2)/(x^2-2x)与(x-1)/(x^2-4x+4)
人气:126 ℃ 时间:2020-02-03 06:50:47
解答
(x+2)/(x^2-2x)=(x+2)/x(x-2)=(x+2)(x-2)/x(x-2)^2=(x^2-4)/x(x-2)^2
(x-1)/(x^2-4x+4)=(x-1)/(x-2)^2=x(x-1)/x(x-2)^2=(x^2-x)/x(x-2)^2
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